/** *************************************************************************** * @remark approximate Pi adding n terms from an arithmetic series * * * * pi is the sum of terns Tn for i = 0, 1, . . . * * where t0 = T1 = 1 and T(n) = 2nT(n-1)/(2(2n+1)) * * * * for 0 <= i <= numTerms, this sum is evaluated * * from largest term to smallest, and * * from smallest term to largest * * * * @author Henry M. Walker * * @file pi-approx.c * * @date Summer, 2023 * * * * @remark References * * @remark Consequences of Data Representation on Programming * https://blue.cs.sonoma.edu/~hwalker/courses/415-sonoma.sp23/readings/data-rep-consequences.html * @remark Wilkpedia article on Leibniz formula for π * * combining terms pairwise from a Taylor's series https://en.wikipedia.org/wiki/Leibniz_formula_for_π * @remark Series that converge to π quickly * https://math.stackexchange.com/questions/14113/series-that-converge-to-pi-quickly * * *****************************************************************************/ #include int main ( ) { printf ("approximating Pi, based on a Taylor series and algebra\n"); double actualPi = 3.1415926535897932384626433; int numTerms; printf ("Enter number of terms: "); scanf ("%d", &numTerms); // Set up array for terms of series double T[numTerms +1]; T[0] = 2.0; T[1] = 2.0/3.0; int i; for (i = 2; i <= numTerms; i++) { T[i] = 2.0 * i * T[i-1] / (2.0 * (2.0*i+1.0)); } printf ("first two terms computed: T[0]: %15.12lf, T[1]: %15.12lf,\n", T[0], T[1]); printf (" last two terms computed: T[%d]: %15.12lf, T[%d]: %15.12lf,\n\n", numTerms-1, T[numTerms-1], numTerms, T[numTerms]); //print table headers printf (" approximation actual value (to 16 places) error\n\n"); // adding terms with i from 0 to numTerms double sum = 0; for (i = 0 ; i < numTerms ; i++) { sum += T[i]; } printf ("number terms: %d\n", numTerms+1); printf (" i goes 0 to %d: %18.16lf", numTerms, sum); printf (" %20.16lf", actualPi); printf (" %20.16lf\n", actualPi - sum); sum = 0; for (i = numTerms-1 ; i >= 0 ; i--) { sum += T[i]; } printf (" i goes %d to 0: %18.16lf", numTerms, sum); printf (" %20.16lf", actualPi); printf (" %20.16lf\n\n", actualPi - sum); return 0; }